3[y-2]=5[y+2]

Solution for 3[y-2]=5[y+2] equation:

Simplifying
3[y + -2] = 5[y + 2]

Reorder the terms:
3[-2 + y] = 5[y + 2]
[-2 * 3 + y * 3] = 5[y + 2]
[-6 + 3y] = 5[y + 2]

Reorder the terms:
-6 + 3y = 5[2 + y]
-6 + 3y = [2 * 5 + y * 5]
-6 + 3y = [10 + 5y]

Solving
-6 + 3y = 10 + 5y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-5y' to each side of the equation.
-6 + 3y + -5y = 10 + 5y + -5y

Combine like terms: 3y + -5y = -2y
-6 + -2y = 10 + 5y + -5y

Combine like terms: 5y + -5y = 0
-6 + -2y = 10 + 0
-6 + -2y = 10

Add '6' to each side of the equation.
-6 + 6 + -2y = 10 + 6

Combine like terms: -6 + 6 = 0
0 + -2y = 10 + 6
-2y = 10 + 6

Combine like terms: 10 + 6 = 16
-2y = 16

Divide each side by '-2'.
y = -8

Simplifying
y = -8